(b^2-1)(b^2+3)=

Solution for (b^2-1)(b^2+3)= equation:

Simplifying
(b2 + -1)(b2 + 3) = 0

Reorder the terms:
(-1 + b2)(b2 + 3) = 0

Reorder the terms:
(-1 + b2)(3 + b2) = 0

Multiply (-1 + b2) * (3 + b2)
(-1(3 + b2) + b2(3 + b2)) = 0
((3 * -1 + b2 * -1) + b2(3 + b2)) = 0
((-3 + -1b2) + b2(3 + b2)) = 0
(-3 + -1b2 + (3 * b2 + b2 * b2)) = 0
(-3 + -1b2 + (3b2 + b4)) = 0

Combine like terms: -1b2 + 3b2 = 2b2
(-3 + 2b2 + b4) = 0

Solving
-3 + 2b2 + b4 = 0

Solving for variable 'b'.

Factor a trinomial.
(-3 + -1b2)(1 + -1b2) = 0

Factor a difference between two squares.
(-3 + -1b2)((1 + b)(1 + -1b)) = 0

Subproblem 1
Set the factor '(-3 + -1b2)' equal to zero and attempt to solve:

Simplifying
-3 + -1b2 = 0

Solving
-3 + -1b2 = 0

Move all terms containing b to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1b2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1b2 = 0 + 3
-1b2 = 0 + 3

Combine like terms: 0 + 3 = 3
-1b2 = 3

Divide each side by '-1'.
b2 = -3

Simplifying
b2 = -3

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Subproblem 3
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Solution
b = {-1, 1}